如何在VB6中将十六进制字符串转换为字节数组

问题描述

我有以下字节数组.

Dim Template(1023) As Byte

然后我调用指纹扫描仪设备函数并返回以下内容:

Then i call the fingerprint scanner device function and returns the following:

Template(0) = 70
Template(1) = 77
Template(2) = 82
...
Template(1023) = 0

然后我将字节数组转换为十六进制字符串，如下所示(查看附图):

Then i convert the Bytes array into a string hex as follows (view attached image):

Dim n As Long, i As Long
ByteArrayToHexStr = Space$(3 * (UBound(Template) - LBound(Template)) + 2)
n = 1
For i = LBound(Template) To UBound(Template)
     Mid$(ByteArrayToHexStr, n, 2) = Right$("00" & Hex$(b(i)), 2)
    n = n + 3
Next

字节数组转换成十六进制字符串如何将十六进制字符串再次转换为字节数组?

Byte Array converted into Hex String How can i convert the hex string into a byte array again?

谢谢！！

推荐答案

可以手动输入的花式版本:

Fancy version tolerant of manual entry:

Private Function BytesToHex(ByRef Bytes() As Byte) As String
    'Quick and dirty Byte array to hex String, format:
    '
    '   "HH HH HH"

    Dim LB As Long
    Dim ByteCount As Long
    Dim BytePos As Integer

    LB = LBound(Bytes)
    ByteCount = UBound(Bytes) - LB + 1
    If ByteCount < 1 Then Exit Function
    BytesToHex = Space$(3 * (ByteCount - 1) + 2)
    For BytePos = LB To UBound(Bytes)
        Mid$(BytesToHex, 3 * (BytePos - LB) + 1, 2) = _
            Right$("0" & Hex$(Bytes(BytePos)), 2)
    Next
End Function

Private Function HexToBytes(ByVal HexString As String) As Byte()
    'Quick and dirty hex String to Byte array.  Accepts:
    '
    '   "HH HH HH"
    '   "HHHHHH"
    '   "H HH H"
    '   "HH,HH,     HH" and so on.

    Dim Bytes() As Byte
    Dim HexPos As Integer
    Dim HexDigit As Integer
    Dim BytePos As Integer
    Dim Digits As Integer

    ReDim Bytes(Len(HexString)  2)  'Initial estimate.
    For HexPos = 1 To Len(HexString)
        HexDigit = InStr("0123456789ABCDEF", _
                         UCase$(Mid$(HexString, HexPos, 1))) - 1
        If HexDigit >= 0 Then
            If BytePos > UBound(Bytes) Then
                'Add some room, we'll add room for 4 more to decrease
                'how often we end up doing this expensive step:
                ReDim Preserve Bytes(UBound(Bytes) + 4)
            End If
            Bytes(BytePos) = Bytes(BytePos) * &H10 + HexDigit
            Digits = Digits + 1
        End If
        If Digits = 2 Or HexDigit < 0 Then
            If Digits > 0 Then BytePos = BytePos + 1
            Digits = 0
        End If
    Next
    If Digits = 0 Then BytePos = BytePos - 1
    If BytePos < 0 Then
        Bytes = "" 'Empty.
    Else
        ReDim Preserve Bytes(BytePos)
    End If
    HexToBytes = Bytes
End Function

这篇关于如何在VB6中将十六进制字符串转换为字节数组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，WP2