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队列<字符串&>错误

本文介绍了队列&lt;字符串&amp;&gt;错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个有趣的情况.

我有一堆包含字符串的结构.

I have a bunch of structs that hold a string.

struct foo
{
    string mStringName;
}
vector<foo> mFoos;

我还有一个字符串引用队列

I also have a queue of string references

queue<string&> mStringQueue;

最后,我有一个接受 const 字符串的函数&

And finally, I have a function that accepts a const string&

void Bar(const string&);

情况是这样的.

//...in some loop
currentFoo = mFoos[index];

// Queue up the string name.
mStringQueue.push(currentFoo.mStringName);


//...Later on, go through our queue and pass each one to the function.

for (int queueIndex = 0; queueIndex < mStringQueue.size(); queueIndex++)
{
    Bar(mStringQueue.front());
    mStringQueue.pop();
}

这给了我以下编译错误:

This gives me the following compile error:

错误 C2664: ‘std::queue<_Ty>::push’ : 无法将参数 1 从 ‘String’ 转换为 ‘String &(&)’

error C2664: ‘std::queue<_Ty>::push’ : cannot convert parameter 1 from ‘String’ to ‘String &(&)’

我在思考字符串引用之类的问题时遇到了麻烦,因此我们将不胜感激任何帮助

I’m definitley having trouble wrapping my mind around string references and whatnot, so any help would be greatly appreciated

推荐答案

引用类型不符合标准容器中可以使用的类型的要求.特别是它们是不可复制的.请注意,虽然引用的对象可以复制或不可复制,但引用本身永远不可复制.

Reference types do not meet the requirements of types that can be used in standard containers. In particular they are not copyable. Note that while the referenced object can be copyable or not, the reference itself is never copyable.

另一种方法是存储可复制的指针.

The alternative is to store pointers, which are copyable.

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